There are other methods for this:
a = a * b
b = a / b
a = a / b
Posted by Gerard on September 16, 2006 at 10:45 AM.
Re: Other ways
There are indeed other ways as well, but they use more processor cycles usually. Xor is efficient simply because it uses a single processor cycle and can't cause any range overflow. Also, the method above is efficient because it uses a single operation, which makes it easier to integrate into specialised microprocessors for example.
Another method with similar performaces can be using:
a = a + b
b = a - b
a = a - b
But then again, this needs two operations (sum and difference - which can be made with negation and another sum), but it still uses more cycles than a simple xor.
Posted by Indy on September 16, 2006 at 12:32 PM.
Not Other Ways
The two other ways noted above presuppose that variable a has sufficient bits available to store the sum or product of a and b.
The original method does not have this restriction.
Posted by Mike on October 27, 2006 at 01:39 PM.
Add and subtract just have to be invertible no actually capable of preserving the intermediate range
title says it all
Posted by Anon Ymous on October 31, 2006 at 11:32 PM.
a ^= b;
b ^= a;
a ^= b;
Posted by Larry on December 19, 2009 at 07:27 PM.
post o post
currently, actually no idea
Posted by want to say ya on August 25, 2010 at 08:59 AM.
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